Finding the percentage | HackerRank

The provided code stub will read in a dictionary containing key/value pairs of name:[marks] for a list of students. Print the average of the marks array for the student name provided, showing 2 places after the decimal.

Example

The query_name is 'beta'. beta's average score is .

Input Format

The first line contains the integer , the number of students' records. The next  lines contain the names and marks obtained by a student, each value separated by a space. The final line contains query_name, the name of a student to query.

Constraints

• 2 <= n < 10
• 0 <= marks[I] <= 100
• Length of marks array = 3

Output Format

Print one line: The average of the marks obtained by the particular student correct to 2 decimal places.

Sample Input 0

3

Krishna 67 68 69

Arjun 70 98 63

Malika 52 56 60

Malika

Sample Output 0

56.00

Explanation 0

Marks for Malika are  whose average is (52+56+60)/3 ==>> 56

Sample Input 1

2

Harsh 25 26.5 28

Anurag 26 28 30

Harsh

Sample Output 1

26.50

Solution

marks = {}

for _ in range(int(input())):

    line = input().split()

    marks[line[0]] = list(map(float, line[1:]))

print('%.2f' %(sum(marks[input()])/3))